Optimal. Leaf size=139 \[ -\frac {A b-2 a B-(b B-2 A c) x^2}{4 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^2}-\frac {3 (b B-2 A c) \left (b+2 c x^2\right )}{4 \left (b^2-4 a c\right )^2 \left (a+b x^2+c x^4\right )}+\frac {3 c (b B-2 A c) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{5/2}} \]
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Rubi [A]
time = 0.09, antiderivative size = 139, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {1261, 652, 628,
632, 212} \begin {gather*} \frac {3 c (b B-2 A c) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{5/2}}-\frac {3 \left (b+2 c x^2\right ) (b B-2 A c)}{4 \left (b^2-4 a c\right )^2 \left (a+b x^2+c x^4\right )}-\frac {-2 a B-\left (x^2 (b B-2 A c)\right )+A b}{4 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 628
Rule 632
Rule 652
Rule 1261
Rubi steps
\begin {align*} \int \frac {x \left (A+B x^2\right )}{\left (a+b x^2+c x^4\right )^3} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {A+B x}{\left (a+b x+c x^2\right )^3} \, dx,x,x^2\right )\\ &=-\frac {A b-2 a B-(b B-2 A c) x^2}{4 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^2}+\frac {(3 (b B-2 A c)) \text {Subst}\left (\int \frac {1}{\left (a+b x+c x^2\right )^2} \, dx,x,x^2\right )}{4 \left (b^2-4 a c\right )}\\ &=-\frac {A b-2 a B-(b B-2 A c) x^2}{4 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^2}-\frac {3 (b B-2 A c) \left (b+2 c x^2\right )}{4 \left (b^2-4 a c\right )^2 \left (a+b x^2+c x^4\right )}-\frac {(3 c (b B-2 A c)) \text {Subst}\left (\int \frac {1}{a+b x+c x^2} \, dx,x,x^2\right )}{2 \left (b^2-4 a c\right )^2}\\ &=-\frac {A b-2 a B-(b B-2 A c) x^2}{4 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^2}-\frac {3 (b B-2 A c) \left (b+2 c x^2\right )}{4 \left (b^2-4 a c\right )^2 \left (a+b x^2+c x^4\right )}+\frac {(3 c (b B-2 A c)) \text {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c x^2\right )}{\left (b^2-4 a c\right )^2}\\ &=-\frac {A b-2 a B-(b B-2 A c) x^2}{4 \left (b^2-4 a c\right ) \left (a+b x^2+c x^4\right )^2}-\frac {3 (b B-2 A c) \left (b+2 c x^2\right )}{4 \left (b^2-4 a c\right )^2 \left (a+b x^2+c x^4\right )}+\frac {3 c (b B-2 A c) \tanh ^{-1}\left (\frac {b+2 c x^2}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{5/2}}\\ \end {align*}
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Mathematica [A]
time = 0.09, size = 142, normalized size = 1.02 \begin {gather*} \frac {-\frac {3 (b B-2 A c) \left (b+2 c x^2\right )}{a+b x^2+c x^4}+\frac {\left (b^2-4 a c\right ) \left (B \left (2 a+b x^2\right )-A \left (b+2 c x^2\right )\right )}{\left (a+b x^2+c x^4\right )^2}-\frac {12 c (b B-2 A c) \tan ^{-1}\left (\frac {b+2 c x^2}{\sqrt {-b^2+4 a c}}\right )}{\sqrt {-b^2+4 a c}}}{4 \left (b^2-4 a c\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.08, size = 147, normalized size = 1.06
method | result | size |
default | \(\frac {\left (2 A c -b B \right ) x^{2}+A b -2 a B}{4 \left (4 a c -b^{2}\right ) \left (c \,x^{4}+b \,x^{2}+a \right )^{2}}+\frac {3 \left (2 A c -b B \right ) \left (\frac {2 c \,x^{2}+b}{\left (4 a c -b^{2}\right ) \left (c \,x^{4}+b \,x^{2}+a \right )}+\frac {4 c \arctan \left (\frac {2 c \,x^{2}+b}{\sqrt {4 a c -b^{2}}}\right )}{\left (4 a c -b^{2}\right )^{\frac {3}{2}}}\right )}{4 \left (4 a c -b^{2}\right )}\) | \(147\) |
risch | \(\frac {\frac {3 c^{2} \left (2 A c -b B \right ) x^{6}}{2 \left (16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}\right )}+\frac {9 b c \left (2 A c -b B \right ) x^{4}}{4 \left (16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}\right )}+\frac {\left (5 a c +b^{2}\right ) \left (2 A c -b B \right ) x^{2}}{32 a^{2} c^{2}-16 a \,b^{2} c +2 b^{4}}+\frac {10 A a b c -A \,b^{3}-8 a^{2} c B -B a \,b^{2}}{64 a^{2} c^{2}-32 a \,b^{2} c +4 b^{4}}}{\left (c \,x^{4}+b \,x^{2}+a \right )^{2}}-\frac {3 c^{2} \ln \left (\left (\left (-4 a c +b^{2}\right )^{\frac {5}{2}}-16 a^{2} b \,c^{2}+8 a \,b^{3} c -b^{5}\right ) x^{2}-32 a^{3} c^{2}+16 a^{2} b^{2} c -2 b^{4} a \right ) A}{\left (-4 a c +b^{2}\right )^{\frac {5}{2}}}+\frac {3 c \ln \left (\left (\left (-4 a c +b^{2}\right )^{\frac {5}{2}}-16 a^{2} b \,c^{2}+8 a \,b^{3} c -b^{5}\right ) x^{2}-32 a^{3} c^{2}+16 a^{2} b^{2} c -2 b^{4} a \right ) b B}{2 \left (-4 a c +b^{2}\right )^{\frac {5}{2}}}+\frac {3 c^{2} \ln \left (\left (\left (-4 a c +b^{2}\right )^{\frac {5}{2}}+16 a^{2} b \,c^{2}-8 a \,b^{3} c +b^{5}\right ) x^{2}+32 a^{3} c^{2}-16 a^{2} b^{2} c +2 b^{4} a \right ) A}{\left (-4 a c +b^{2}\right )^{\frac {5}{2}}}-\frac {3 c \ln \left (\left (\left (-4 a c +b^{2}\right )^{\frac {5}{2}}+16 a^{2} b \,c^{2}-8 a \,b^{3} c +b^{5}\right ) x^{2}+32 a^{3} c^{2}-16 a^{2} b^{2} c +2 b^{4} a \right ) b B}{2 \left (-4 a c +b^{2}\right )^{\frac {5}{2}}}\) | \(488\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 542 vs.
\(2 (131) = 262\).
time = 0.39, size = 1109, normalized size = 7.98 \begin {gather*} \left [-\frac {6 \, {\left (B b^{3} c^{2} + 8 \, A a c^{4} - 2 \, {\left (2 \, B a b + A b^{2}\right )} c^{3}\right )} x^{6} + B a b^{4} + A b^{5} + 9 \, {\left (B b^{4} c + 8 \, A a b c^{3} - 2 \, {\left (2 \, B a b^{2} + A b^{3}\right )} c^{2}\right )} x^{4} - 8 \, {\left (4 \, B a^{3} - 5 \, A a^{2} b\right )} c^{2} + 2 \, {\left (B b^{5} + 40 \, A a^{2} c^{3} - 2 \, {\left (10 \, B a^{2} b + A a b^{2}\right )} c^{2} + {\left (B a b^{3} - 2 \, A b^{4}\right )} c\right )} x^{2} + 6 \, {\left ({\left (B b c^{3} - 2 \, A c^{4}\right )} x^{8} + 2 \, {\left (B b^{2} c^{2} - 2 \, A b c^{3}\right )} x^{6} + B a^{2} b c - 2 \, A a^{2} c^{2} + {\left (B b^{3} c - 4 \, A a c^{3} + 2 \, {\left (B a b - A b^{2}\right )} c^{2}\right )} x^{4} + 2 \, {\left (B a b^{2} c - 2 \, A a b c^{2}\right )} x^{2}\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, c^{2} x^{4} + 2 \, b c x^{2} + b^{2} - 2 \, a c - {\left (2 \, c x^{2} + b\right )} \sqrt {b^{2} - 4 \, a c}}{c x^{4} + b x^{2} + a}\right ) + 2 \, {\left (2 \, B a^{2} b^{2} - 7 \, A a b^{3}\right )} c}{4 \, {\left ({\left (b^{6} c^{2} - 12 \, a b^{4} c^{3} + 48 \, a^{2} b^{2} c^{4} - 64 \, a^{3} c^{5}\right )} x^{8} + a^{2} b^{6} - 12 \, a^{3} b^{4} c + 48 \, a^{4} b^{2} c^{2} - 64 \, a^{5} c^{3} + 2 \, {\left (b^{7} c - 12 \, a b^{5} c^{2} + 48 \, a^{2} b^{3} c^{3} - 64 \, a^{3} b c^{4}\right )} x^{6} + {\left (b^{8} - 10 \, a b^{6} c + 24 \, a^{2} b^{4} c^{2} + 32 \, a^{3} b^{2} c^{3} - 128 \, a^{4} c^{4}\right )} x^{4} + 2 \, {\left (a b^{7} - 12 \, a^{2} b^{5} c + 48 \, a^{3} b^{3} c^{2} - 64 \, a^{4} b c^{3}\right )} x^{2}\right )}}, -\frac {6 \, {\left (B b^{3} c^{2} + 8 \, A a c^{4} - 2 \, {\left (2 \, B a b + A b^{2}\right )} c^{3}\right )} x^{6} + B a b^{4} + A b^{5} + 9 \, {\left (B b^{4} c + 8 \, A a b c^{3} - 2 \, {\left (2 \, B a b^{2} + A b^{3}\right )} c^{2}\right )} x^{4} - 8 \, {\left (4 \, B a^{3} - 5 \, A a^{2} b\right )} c^{2} + 2 \, {\left (B b^{5} + 40 \, A a^{2} c^{3} - 2 \, {\left (10 \, B a^{2} b + A a b^{2}\right )} c^{2} + {\left (B a b^{3} - 2 \, A b^{4}\right )} c\right )} x^{2} - 12 \, {\left ({\left (B b c^{3} - 2 \, A c^{4}\right )} x^{8} + 2 \, {\left (B b^{2} c^{2} - 2 \, A b c^{3}\right )} x^{6} + B a^{2} b c - 2 \, A a^{2} c^{2} + {\left (B b^{3} c - 4 \, A a c^{3} + 2 \, {\left (B a b - A b^{2}\right )} c^{2}\right )} x^{4} + 2 \, {\left (B a b^{2} c - 2 \, A a b c^{2}\right )} x^{2}\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {{\left (2 \, c x^{2} + b\right )} \sqrt {-b^{2} + 4 \, a c}}{b^{2} - 4 \, a c}\right ) + 2 \, {\left (2 \, B a^{2} b^{2} - 7 \, A a b^{3}\right )} c}{4 \, {\left ({\left (b^{6} c^{2} - 12 \, a b^{4} c^{3} + 48 \, a^{2} b^{2} c^{4} - 64 \, a^{3} c^{5}\right )} x^{8} + a^{2} b^{6} - 12 \, a^{3} b^{4} c + 48 \, a^{4} b^{2} c^{2} - 64 \, a^{5} c^{3} + 2 \, {\left (b^{7} c - 12 \, a b^{5} c^{2} + 48 \, a^{2} b^{3} c^{3} - 64 \, a^{3} b c^{4}\right )} x^{6} + {\left (b^{8} - 10 \, a b^{6} c + 24 \, a^{2} b^{4} c^{2} + 32 \, a^{3} b^{2} c^{3} - 128 \, a^{4} c^{4}\right )} x^{4} + 2 \, {\left (a b^{7} - 12 \, a^{2} b^{5} c + 48 \, a^{3} b^{3} c^{2} - 64 \, a^{4} b c^{3}\right )} x^{2}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 661 vs.
\(2 (134) = 268\).
time = 163.74, size = 661, normalized size = 4.76 \begin {gather*} \frac {3 c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) \log {\left (x^{2} + \frac {- 6 A b c^{2} + 3 B b^{2} c - 192 a^{3} c^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) + 144 a^{2} b^{2} c^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) - 36 a b^{4} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) + 3 b^{6} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right )}{- 12 A c^{3} + 6 B b c^{2}} \right )}}{2} - \frac {3 c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) \log {\left (x^{2} + \frac {- 6 A b c^{2} + 3 B b^{2} c + 192 a^{3} c^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) - 144 a^{2} b^{2} c^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) + 36 a b^{4} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right ) - 3 b^{6} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \left (- 2 A c + B b\right )}{- 12 A c^{3} + 6 B b c^{2}} \right )}}{2} + \frac {10 A a b c - A b^{3} - 8 B a^{2} c - B a b^{2} + x^{6} \cdot \left (12 A c^{3} - 6 B b c^{2}\right ) + x^{4} \cdot \left (18 A b c^{2} - 9 B b^{2} c\right ) + x^{2} \cdot \left (20 A a c^{2} + 4 A b^{2} c - 10 B a b c - 2 B b^{3}\right )}{64 a^{4} c^{2} - 32 a^{3} b^{2} c + 4 a^{2} b^{4} + x^{8} \cdot \left (64 a^{2} c^{4} - 32 a b^{2} c^{3} + 4 b^{4} c^{2}\right ) + x^{6} \cdot \left (128 a^{2} b c^{3} - 64 a b^{3} c^{2} + 8 b^{5} c\right ) + x^{4} \cdot \left (128 a^{3} c^{3} - 24 a b^{4} c + 4 b^{6}\right ) + x^{2} \cdot \left (128 a^{3} b c^{2} - 64 a^{2} b^{3} c + 8 a b^{5}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 5.90, size = 208, normalized size = 1.50 \begin {gather*} -\frac {3 \, {\left (B b c - 2 \, A c^{2}\right )} \arctan \left (\frac {2 \, c x^{2} + b}{\sqrt {-b^{2} + 4 \, a c}}\right )}{{\left (b^{4} - 8 \, a b^{2} c + 16 \, a^{2} c^{2}\right )} \sqrt {-b^{2} + 4 \, a c}} - \frac {6 \, B b c^{2} x^{6} - 12 \, A c^{3} x^{6} + 9 \, B b^{2} c x^{4} - 18 \, A b c^{2} x^{4} + 2 \, B b^{3} x^{2} + 10 \, B a b c x^{2} - 4 \, A b^{2} c x^{2} - 20 \, A a c^{2} x^{2} + B a b^{2} + A b^{3} + 8 \, B a^{2} c - 10 \, A a b c}{4 \, {\left (c x^{4} + b x^{2} + a\right )}^{2} {\left (b^{4} - 8 \, a b^{2} c + 16 \, a^{2} c^{2}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.59, size = 517, normalized size = 3.72 \begin {gather*} \frac {3\,c\,\mathrm {atan}\left (\frac {\left (x^2\,\left (\frac {3\,c\,\left (2\,A\,c-B\,b\right )\,\left (6\,A\,c^4-3\,B\,b\,c^3\right )}{a\,{\left (4\,a\,c-b^2\right )}^{9/2}\,\left (16\,a^2\,c^2-8\,a\,b^2\,c+b^4\right )}+\frac {9\,b\,c^2\,{\left (2\,A\,c-B\,b\right )}^2\,\left (32\,a^2\,b\,c^4-16\,a\,b^3\,c^3+2\,b^5\,c^2\right )}{2\,a\,{\left (4\,a\,c-b^2\right )}^{15/2}\,\left (16\,a^2\,c^2-8\,a\,b^2\,c+b^4\right )}\right )+\frac {18\,b\,c^4\,{\left (2\,A\,c-B\,b\right )}^2}{{\left (4\,a\,c-b^2\right )}^{15/2}}\right )\,\left (b^4\,{\left (4\,a\,c-b^2\right )}^5+16\,a^2\,c^2\,{\left (4\,a\,c-b^2\right )}^5-8\,a\,b^2\,c\,{\left (4\,a\,c-b^2\right )}^5\right )}{72\,A^2\,c^6-72\,A\,B\,b\,c^5+18\,B^2\,b^2\,c^4}\right )\,\left (2\,A\,c-B\,b\right )}{{\left (4\,a\,c-b^2\right )}^{5/2}}-\frac {\frac {8\,B\,c\,a^2+B\,a\,b^2-10\,A\,c\,a\,b+A\,b^3}{4\,\left (16\,a^2\,c^2-8\,a\,b^2\,c+b^4\right )}-\frac {9\,x^4\,\left (2\,A\,b\,c^2-B\,b^2\,c\right )}{4\,\left (16\,a^2\,c^2-8\,a\,b^2\,c+b^4\right )}+\frac {x^2\,\left (B\,b^3-2\,A\,b^2\,c+5\,B\,a\,b\,c-10\,A\,a\,c^2\right )}{2\,\left (16\,a^2\,c^2-8\,a\,b^2\,c+b^4\right )}-\frac {3\,c^2\,x^6\,\left (2\,A\,c-B\,b\right )}{2\,\left (16\,a^2\,c^2-8\,a\,b^2\,c+b^4\right )}}{x^4\,\left (b^2+2\,a\,c\right )+a^2+c^2\,x^8+2\,a\,b\,x^2+2\,b\,c\,x^6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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